Base | Representation |
---|---|
bin | 1011000011001111001001… |
… | …0011110001010000001011 |
3 | 1121000112212121120011022110 |
4 | 2300303302103301100023 |
5 | 3043032134043004320 |
6 | 41501423451553403 |
7 | 2362553044414011 |
oct | 260636223612013 |
9 | 47015777504273 |
10 | 12150232781835 |
11 | 3964980716435 |
12 | 144296845b863 |
13 | 6a19ba263575 |
14 | 3001082468b1 |
15 | 1610c71825e0 |
hex | b0cf24f140b |
12150232781835 has 16 divisors (see below), whose sum is σ = 19440582435360. Its totient is φ = 6480054155520.
The previous prime is 12150232781833. The next prime is 12150232781917. The reversal of 12150232781835 is 53818723205121.
It is not a de Polignac number, because 12150232781835 - 21 = 12150232781833 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12150232781833) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2924170 + ... + 5731599.
It is an arithmetic number, because the mean of its divisors is an integer number (1215036402210).
Almost surely, 212150232781835 is an apocalyptic number.
12150232781835 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12150232781835 is a deficient number, since it is larger than the sum of its proper divisors (7290349653525).
12150232781835 is an equidigital number, since it uses as much as digits as its factorization.
12150232781835 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8749358.
The product of its (nonzero) digits is 806400, while the sum is 48.
Adding to 12150232781835 its reverse (53818723205121), we get a palindrome (65968955986956).
The spelling of 12150232781835 in words is "twelve trillion, one hundred fifty billion, two hundred thirty-two million, seven hundred eighty-one thousand, eight hundred thirty-five".
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