Base | Representation |
---|---|
bin | 1011000011001111001011… |
… | …1000001110110100010011 |
3 | 1121000112220021112202210211 |
4 | 2300303302320032310103 |
5 | 3043032144014340430 |
6 | 41501424432504551 |
7 | 2362553221563505 |
oct | 260636270166423 |
9 | 47015807482724 |
10 | 12150242340115 |
11 | 3964986054740 |
12 | 144296b6ab157 |
13 | 6a19bc22c059 |
14 | 300109613d75 |
15 | 1610c7e1e72a |
hex | b0cf2e0ed13 |
12150242340115 has 16 divisors (see below), whose sum is σ = 15909843168000. Its totient is φ = 8834278007520.
The previous prime is 12150242340097. The next prime is 12150242340127. The reversal of 12150242340115 is 51104324205121.
12150242340115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12150242340115 - 219 = 12150241815827 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28056615 + ... + 28486384.
It is an arithmetic number, because the mean of its divisors is an integer number (994365198000).
Almost surely, 212150242340115 is an apocalyptic number.
12150242340115 is a deficient number, since it is larger than the sum of its proper divisors (3759600827885).
12150242340115 is a wasteful number, since it uses less digits than its factorization.
12150242340115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56546922.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 12150242340115 its reverse (51104324205121), we get a palindrome (63254566545236).
The spelling of 12150242340115 in words is "twelve trillion, one hundred fifty billion, two hundred forty-two million, three hundred forty thousand, one hundred fifteen".
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