1215150353113 has 4 divisors (see below), whose sum is σ = 1217566159488. Its totient is φ = 1212734546740.

The previous prime is 1215150353099. The next prime is 1215150353147. The reversal of 1215150353113 is 3113530515121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1215150353113 - 2²¹ = 1215148255961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1215150356113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1207902433 + ... + 1207903438.

It is an arithmetic number, because the mean of its divisors is an integer number (304391539872).

Almost surely, 2^{1215150353113} is an apocalyptic number.

It is an amenable number.

1215150353113 is a deficient number, since it is larger than the sum of its proper divisors (2415806375).

1215150353113 is an equidigital number, since it uses as much as digits as its factorization.

1215150353113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2415806374.

The product of its (nonzero) digits is 6750, while the sum is 31.

Adding to 1215150353113 its reverse (3113530515121), we get a palindrome (4328680868234).

The spelling of 1215150353113 in words is "one trillion, two hundred fifteen billion, one hundred fifty million, three hundred fifty-three thousand, one hundred thirteen".