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12152113 = 41833571
BaseRepresentation
bin101110010110…
…110100110001
3211212101120021
4232112310301
511102331423
61112243441
7205201621
oct56266461
924771507
1012152113
116950076
1240a0581
1326962cc
141884881
15110095d
hexb96d31

12152113 has 8 divisors (see below), whose sum is σ = 12602016. Its totient is φ = 11709600.

The previous prime is 12152099. The next prime is 12152137. The reversal of 12152113 is 31125121.

12152113 is nontrivially palindromic in base 14.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12152113 - 25 = 12152081 is a prime.

It is a super-3 number, since 3×121521133 (a number of 22 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12152143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1618 + ... + 5188.

It is an arithmetic number, because the mean of its divisors is an integer number (1575252).

Almost surely, 212152113 is an apocalyptic number.

It is an amenable number.

12152113 is a deficient number, since it is larger than the sum of its proper divisors (449903).

12152113 is an equidigital number, since it uses as much as digits as its factorization.

12152113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3695.

The product of its digits is 60, while the sum is 16.

The square root of 12152113 is about 3485.9880952178. The cubic root of 12152113 is about 229.9061557919.

Adding to 12152113 its reverse (31125121), we get a palindrome (43277234).

The spelling of 12152113 in words is "twelve million, one hundred fifty-two thousand, one hundred thirteen".

Divisors: 1 41 83 3403 3571 146411 296393 12152113