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12152610433 = 65918440987
BaseRepresentation
bin10110101000101101…
…00001111010000001
31011100221021120111201
423110112201322001
5144342032013213
65325520341201
7610103325055
oct132426417201
934327246451
1012152610433
1151769170a7
122431a74801
1311b8968962
14833dc5c65
154b1d686dd
hex2d45a1e81

12152610433 has 4 divisors (see below), whose sum is σ = 12171052080. Its totient is φ = 12134168788.

The previous prime is 12152610409. The next prime is 12152610439. The reversal of 12152610433 is 33401625121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33401625121 = 227147143723.

It is a cyclic number.

It is not a de Polignac number, because 12152610433 - 25 = 12152610401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12152610439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9219835 + ... + 9221152.

It is an arithmetic number, because the mean of its divisors is an integer number (3042763020).

Almost surely, 212152610433 is an apocalyptic number.

It is an amenable number.

12152610433 is a deficient number, since it is larger than the sum of its proper divisors (18441647).

12152610433 is an equidigital number, since it uses as much as digits as its factorization.

12152610433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18441646.

The product of its (nonzero) digits is 4320, while the sum is 28.

The spelling of 12152610433 in words is "twelve billion, one hundred fifty-two million, six hundred ten thousand, four hundred thirty-three".

Divisors: 1 659 18440987 12152610433