1215401335051 has 4 divisors (see below), whose sum is σ = 1226157099192. Its totient is φ = 1204645570912.

The previous prime is 1215401335037. The next prime is 1215401335063. The reversal of 1215401335051 is 1505331045121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1215401335051 - 2⁵ = 1215401335019 is a prime.

It is a super-2 number, since 2×1215401335051² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1215401335021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5377881901 + ... + 5377882126.

It is an arithmetic number, because the mean of its divisors is an integer number (306539274798).

Almost surely, 2^{1215401335051} is an apocalyptic number.

1215401335051 is a deficient number, since it is larger than the sum of its proper divisors (10755764141).

1215401335051 is a wasteful number, since it uses less digits than its factorization.

1215401335051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10755764140.

The product of its (nonzero) digits is 9000, while the sum is 31.

The spelling of 1215401335051 in words is "one trillion, two hundred fifteen billion, four hundred one million, three hundred thirty-five thousand, fifty-one".