Base | Representation |
---|---|
bin | 10001101100000010010… |
… | …010000011010101011011 |
3 | 11022012110021002120020220 |
4 | 101230002102003111123 |
5 | 124403333043001301 |
6 | 2330222140051123 |
7 | 153550366536306 |
oct | 21540222032533 |
9 | 4265407076226 |
10 | 1215514031451 |
11 | 429550a89595 |
12 | 1776a9233aa3 |
13 | 8a81278c685 |
14 | 42b8cb17b3d |
15 | 21941bda936 |
hex | 11b0248355b |
1215514031451 has 16 divisors (see below), whose sum is σ = 1621642270464. Its totient is φ = 809864368544.
The previous prime is 1215514031449. The next prime is 1215514031467. The reversal of 1215514031451 is 1541304155121.
It is a cyclic number.
It is not a de Polignac number, because 1215514031451 - 21 = 1215514031449 is a prime.
It is a super-3 number, since 3×12155140314513 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1215514031651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 54848065 + ... + 54870221.
It is an arithmetic number, because the mean of its divisors is an integer number (101352641904).
Almost surely, 21215514031451 is an apocalyptic number.
1215514031451 is a deficient number, since it is larger than the sum of its proper divisors (406128239013).
1215514031451 is a wasteful number, since it uses less digits than its factorization.
1215514031451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32130.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 1215514031451 its reverse (1541304155121), we get a palindrome (2756818186572).
The spelling of 1215514031451 in words is "one trillion, two hundred fifteen billion, five hundred fourteen million, thirty-one thousand, four hundred fifty-one".
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