121683433 has 4 divisors (see below), whose sum is σ = 128841300. Its totient is φ = 114525568.

The previous prime is 121683431. The next prime is 121683437. The reversal of 121683433 is 334386121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334386121 = 23 ⋅14538527.

It can be written as a sum of positive squares in 2 ways, for example, as 74183769 + 47499664 = 8613^2 + 6892^2 .

It is a cyclic number.

It is not a de Polignac number, because 121683433 - 2¹ = 121683431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121683395 and 121683404.

It is not an unprimeable number, because it can be changed into a prime (121683431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3578908 + ... + 3578941.

It is an arithmetic number, because the mean of its divisors is an integer number (32210325).

Almost surely, 2^121683433 is an apocalyptic number.

It is an amenable number.

121683433 is a deficient number, since it is larger than the sum of its proper divisors (7157867).

121683433 is an equidigital number, since it uses as much as digits as its factorization.

121683433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7157866.

The product of its digits is 10368, while the sum is 31.

The square root of 121683433 is about 11031.0213942318. The cubic root of 121683433 is about 495.5382140294.

The spelling of 121683433 in words is "one hundred twenty-one million, six hundred eighty-three thousand, four hundred thirty-three".