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12200131311233 = 31393552622943
BaseRepresentation
bin1011000110001001000001…
…1111100011011010000001
31121012022200010110002102212
42301202100133203122001
53044341332103424413
641540355110351505
72366300425051055
oct261422037433201
947168603402385
1012200131311233
113984057083088
12145057335b595
136a660cc962c8
143026bd2c1c65
15162547b81ca8
hexb18907e3681

12200131311233 has 4 divisors (see below), whose sum is σ = 12593683934208. Its totient is φ = 11806578688260.

The previous prime is 12200131311157. The next prime is 12200131311241. The reversal of 12200131311233 is 33211313100221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12200131311233 - 212 = 12200131307137 is a prime.

It is a super-2 number, since 2×122001313112332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12200131311199 and 12200131311208.

It is not an unprimeable number, because it can be changed into a prime (12200131311253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196776311441 + ... + 196776311502.

It is an arithmetic number, because the mean of its divisors is an integer number (3148420983552).

Almost surely, 212200131311233 is an apocalyptic number.

It is an amenable number.

12200131311233 is a deficient number, since it is larger than the sum of its proper divisors (393552622975).

12200131311233 is an equidigital number, since it uses as much as digits as its factorization.

12200131311233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 393552622974.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 12200131311233 its reverse (33211313100221), we get a palindrome (45411444411454).

The spelling of 12200131311233 in words is "twelve trillion, two hundred billion, one hundred thirty-one million, three hundred eleven thousand, two hundred thirty-three".

Divisors: 1 31 393552622943 12200131311233