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1220021151001 = 4328372584907
BaseRepresentation
bin10001110000001110111…
…011010110010100011001
311022122002101000221221121
4101300032323112110121
5124442100403313001
62332245303205241
7154100155451452
oct21601673262431
94278071027847
101220021151001
11430454152184
12178546746821
138b080489913
1443099558129
1521b077336a1
hex11c0eed6519

1220021151001 has 4 divisors (see below), whose sum is σ = 1248393735952. Its totient is φ = 1191648566052.

The previous prime is 1220021150981. The next prime is 1220021151023. The reversal of 1220021151001 is 1001511200221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1220021151001 - 223 = 1220012762393 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1220021151091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14186292411 + ... + 14186292496.

It is an arithmetic number, because the mean of its divisors is an integer number (312098433988).

Almost surely, 21220021151001 is an apocalyptic number.

It is an amenable number.

1220021151001 is a deficient number, since it is larger than the sum of its proper divisors (28372584951).

1220021151001 is an equidigital number, since it uses as much as digits as its factorization.

1220021151001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28372584950.

The product of its (nonzero) digits is 40, while the sum is 16.

Adding to 1220021151001 its reverse (1001511200221), we get a palindrome (2221532351222).

The spelling of 1220021151001 in words is "one trillion, two hundred twenty billion, twenty-one million, one hundred fifty-one thousand, one".

Divisors: 1 43 28372584907 1220021151001