Base | Representation |
---|---|
bin | 10001110000010100011… |
… | …111001110001100101011 |
3 | 11022122022212120120202212 |
4 | 101300110133032030223 |
5 | 124442243244103003 |
6 | 2332302434515335 |
7 | 154102400426123 |
oct | 21602437161453 |
9 | 4278285516685 |
10 | 1220114441003 |
11 | 4304a1880357 |
12 | 178571a35b4b |
13 | 8b0968c11c3 |
14 | 430a7abdc83 |
15 | 21b10a0edd8 |
hex | 11c147ce32b |
1220114441003 has 4 divisors (see below), whose sum is σ = 1220153781120. Its totient is φ = 1220075100888.
The previous prime is 1220114440969. The next prime is 1220114441009. The reversal of 1220114441003 is 3001444110221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1220114441003 - 230 = 1219040699179 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1220114441003.
It is not an unprimeable number, because it can be changed into a prime (1220114441009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19623500 + ... + 19685577.
It is an arithmetic number, because the mean of its divisors is an integer number (305038445280).
Almost surely, 21220114441003 is an apocalyptic number.
1220114441003 is a deficient number, since it is larger than the sum of its proper divisors (39340117).
1220114441003 is an equidigital number, since it uses as much as digits as its factorization.
1220114441003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39340116.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1220114441003 its reverse (3001444110221), we get a palindrome (4221558551224).
The spelling of 1220114441003 in words is "one trillion, two hundred twenty billion, one hundred fourteen million, four hundred forty-one thousand, three".
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