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122014000433 = 139385692341
BaseRepresentation
bin111000110100010011…
…0011110010100110001
3102122221100212102201002
41301220212132110301
53444341041003213
6132015155251345
711546422614533
oct1615046362461
9378840772632
10122014000433
11478227a4496
121b7922a9b55
13b6765240c0
145c96a07853
153291bd1658
hex1c6899e531

122014000433 has 4 divisors (see below), whose sum is σ = 131399692788. Its totient is φ = 112628308080.

The previous prime is 122014000417. The next prime is 122014000453. The reversal of 122014000433 is 334000410221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74476047409 + 47537953024 = 272903^2 + 218032^2 .

It is a cyclic number.

It is not a de Polignac number, because 122014000433 - 24 = 122014000417 is a prime.

It is not an unprimeable number, because it can be changed into a prime (122014000453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4692846158 + ... + 4692846183.

It is an arithmetic number, because the mean of its divisors is an integer number (32849923197).

Almost surely, 2122014000433 is an apocalyptic number.

122014000433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

122014000433 is a deficient number, since it is larger than the sum of its proper divisors (9385692355).

122014000433 is an equidigital number, since it uses as much as digits as its factorization.

122014000433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9385692354.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 122014000433 its reverse (334000410221), we get a palindrome (456014410654).

The spelling of 122014000433 in words is "one hundred twenty-two billion, fourteen million, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 13 9385692341 122014000433