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12202111313 = 71743158759
BaseRepresentation
bin10110101110100110…
…10111000101010001
31011111101102110221122
423113103113011101
5144442220030223
65334445332025
7611244143360
oct132723270521
934441373848
1012202111313
1151a1856917
122446567015
1311c5caab12
1483a7cd7d7
154b63955c8
hex2d74d7151

12202111313 has 4 divisors (see below), whose sum is σ = 13945270080. Its totient is φ = 10458952548.

The previous prime is 12202111309. The next prime is 12202111349. The reversal of 12202111313 is 31311120221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12202111313 - 22 = 12202111309 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12202111291 and 12202111300.

It is not an unprimeable number, because it can be changed into a prime (12202111213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 871579373 + ... + 871579386.

It is an arithmetic number, because the mean of its divisors is an integer number (3486317520).

Almost surely, 212202111313 is an apocalyptic number.

It is an amenable number.

12202111313 is a deficient number, since it is larger than the sum of its proper divisors (1743158767).

12202111313 is an equidigital number, since it uses as much as digits as its factorization.

12202111313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1743158766.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 12202111313 its reverse (31311120221), we get a palindrome (43513231534).

The spelling of 12202111313 in words is "twelve billion, two hundred two million, one hundred eleven thousand, three hundred thirteen".

Divisors: 1 7 1743158759 12202111313