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12203022113 = 81194715889
BaseRepresentation
bin10110101110101101…
…10101011100100001
31011111110010202022222
423113112311130201
5144442433201423
65334521040425
7611254655642
oct132726653441
934443122288
1012203022113
1151a2319147
122446926115
1311c6239559
1483a9896c9
154b64c53c8
hex2d75b5721

12203022113 has 8 divisors (see below), whose sum is σ = 12231740640. Its totient is φ = 12174338880.

The previous prime is 12203022107. The next prime is 12203022173. The reversal of 12203022113 is 31122030221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12203022113 - 212 = 12203018017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12203022091 and 12203022100.

It is not an unprimeable number, because it can be changed into a prime (12203022103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 760073 + ... + 775961.

It is an arithmetic number, because the mean of its divisors is an integer number (1528967580).

Almost surely, 212203022113 is an apocalyptic number.

It is an amenable number.

12203022113 is a deficient number, since it is larger than the sum of its proper divisors (28718527).

12203022113 is an equidigital number, since it uses as much as digits as its factorization.

12203022113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17647.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12203022113 its reverse (31122030221), we get a palindrome (43325052334).

The spelling of 12203022113 in words is "twelve billion, two hundred three million, twenty-two thousand, one hundred thirteen".

Divisors: 1 811 947 15889 768017 12885979 15046883 12203022113