122034113 has 4 divisors (see below), whose sum is σ = 127339968. Its totient is φ = 116728260.

The previous prime is 122034097. The next prime is 122034119. The reversal of 122034113 is 311430221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311430221 = 37 ⋅8417033.

It is a cyclic number.

It is not a de Polignac number, because 122034113 - 2⁴ = 122034097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122034091 and 122034100.

It is not an unprimeable number, because it can be changed into a prime (122034119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2652893 + ... + 2652938.

It is an arithmetic number, because the mean of its divisors is an integer number (31834992).

Almost surely, 2^122034113 is an apocalyptic number.

It is an amenable number.

122034113 is a deficient number, since it is larger than the sum of its proper divisors (5305855).

122034113 is an equidigital number, since it uses as much as digits as its factorization.

122034113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5305854.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 122034113 is about 11046.9051322078. The cubic root of 122034113 is about 496.0137886927.

Adding to 122034113 its reverse (311430221), we get a palindrome (433464334).

The spelling of 122034113 in words is "one hundred twenty-two million, thirty-four thousand, one hundred thirteen".