12204014301131 has 4 divisors (see below), whose sum is σ = 12218254692072. Its totient is φ = 12189773910192.

The previous prime is 12204014301119. The next prime is 12204014301151. The reversal of 12204014301131 is 13110341040221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12204014301131 - 2³⁰ = 12202940559307 is a prime.

It is a super-2 number, since 2×12204014301131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12204014301097 and 12204014301106.

It is not an unprimeable number, because it can be changed into a prime (12204014301151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7120194185 + ... + 7120195898.

It is an arithmetic number, because the mean of its divisors is an integer number (3054563673018).

Almost surely, 2^{12204014301131} is an apocalyptic number.

12204014301131 is a deficient number, since it is larger than the sum of its proper divisors (14240390941).

12204014301131 is an equidigital number, since it uses as much as digits as its factorization.

12204014301131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14240390940.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 12204014301131 its reverse (13110341040221), we get a palindrome (25314355341352).

The spelling of 12204014301131 in words is "twelve trillion, two hundred four billion, fourteen million, three hundred one thousand, one hundred thirty-one".