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1220402313041 = 6831786826227
BaseRepresentation
bin10001110000100101101…
…001010111011101010001
311022200001221020222222012
4101300211221113131101
5124443340443004131
62332351200552305
7154112464334162
oct21604551273521
94280057228865
101220402313041
1143062a32092a
12178632322695
138b1114339a2
14430d4017769
1521b2ae2552b
hex11c25a57751

1220402313041 has 4 divisors (see below), whose sum is σ = 1222189139952. Its totient is φ = 1218615486132.

The previous prime is 1220402313037. The next prime is 1220402313077. The reversal of 1220402313041 is 1403132040221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1220402313041 - 22 = 1220402313037 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1220402312998 and 1220402313016.

It is not an unprimeable number, because it can be changed into a prime (1220402313541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893412431 + ... + 893413796.

It is an arithmetic number, because the mean of its divisors is an integer number (305547284988).

Almost surely, 21220402313041 is an apocalyptic number.

It is an amenable number.

1220402313041 is a deficient number, since it is larger than the sum of its proper divisors (1786826911).

1220402313041 is an equidigital number, since it uses as much as digits as its factorization.

1220402313041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1786826910.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1220402313041 its reverse (1403132040221), we get a palindrome (2623534353262).

The spelling of 1220402313041 in words is "one trillion, two hundred twenty billion, four hundred two million, three hundred thirteen thousand, forty-one".

Divisors: 1 683 1786826227 1220402313041