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1220424540115 = 51122189537093
BaseRepresentation
bin10001110000100110111…
…110001001111111010011
311022200010111002020210011
4101300212332021333103
5124443412140240430
62332353313215351
7154113154300144
oct21604676117723
94280114066704
101220424540115
11430640922410
12178639861557
138b115c169c1
14430d6d61acb
1521b2cd6622a
hex11c26f89fd3

1220424540115 has 8 divisors (see below), whose sum is σ = 1597646670768. Its totient is φ = 887581483680.

The previous prime is 1220424540091. The next prime is 1220424540149. The reversal of 1220424540115 is 5110454240221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1220424540115 - 215 = 1220424507347 is a prime.

It is a super-2 number, since 2×12204245401152 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11094768492 + ... + 11094768601.

It is an arithmetic number, because the mean of its divisors is an integer number (199705833846).

Almost surely, 21220424540115 is an apocalyptic number.

1220424540115 is a deficient number, since it is larger than the sum of its proper divisors (377222130653).

1220424540115 is a wasteful number, since it uses less digits than its factorization.

1220424540115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22189537109.

The product of its (nonzero) digits is 12800, while the sum is 31.

Adding to 1220424540115 its reverse (5110454240221), we get a palindrome (6330878780336).

The spelling of 1220424540115 in words is "one trillion, two hundred twenty billion, four hundred twenty-four million, five hundred forty thousand, one hundred fifteen".

Divisors: 1 5 11 55 22189537093 110947685465 244084908023 1220424540115