1220432512139 has 4 divisors (see below), whose sum is σ = 1220807226024. Its totient is φ = 1220057798256.

The previous prime is 1220432512129. The next prime is 1220432512181. The reversal of 1220432512139 is 9312152340221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1220432512139 is a prime.

It is a super-3 number, since 3×1220432512139³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1220432512099 and 1220432512108.

It is not an unprimeable number, because it can be changed into a prime (1220432512129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187352057 + ... + 187358570.

It is an arithmetic number, because the mean of its divisors is an integer number (305201806506).

Almost surely, 2^{1220432512139} is an apocalyptic number.

1220432512139 is a deficient number, since it is larger than the sum of its proper divisors (374713885).

1220432512139 is an equidigital number, since it uses as much as digits as its factorization.

1220432512139 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 374713884.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 1220432512139 in words is "one trillion, two hundred twenty billion, four hundred thirty-two million, five hundred twelve thousand, one hundred thirty-nine".