Base | Representation |
---|---|
bin | 10001110000101011110… |
… | …011001001111100000001 |
3 | 11022200100010111121000211 |
4 | 101300223303021330001 |
5 | 124444043404324101 |
6 | 2332405325314121 |
7 | 154115156636335 |
oct | 21605363117401 |
9 | 4280303447024 |
10 | 1220505542401 |
11 | 430682618652 |
12 | 178660a05941 |
13 | 8b129938352 |
14 | 43103a097c5 |
15 | 21b35016c51 |
hex | 11c2bcc9f01 |
1220505542401 has 4 divisors (see below), whose sum is σ = 1220513461552. Its totient is φ = 1220497623252.
The previous prime is 1220505542393. The next prime is 1220505542437. The reversal of 1220505542401 is 1042455050221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1220505542401 - 23 = 1220505542393 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1220505542491) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3723711 + ... + 4038196.
It is an arithmetic number, because the mean of its divisors is an integer number (305128365388).
Almost surely, 21220505542401 is an apocalyptic number.
It is an amenable number.
1220505542401 is a deficient number, since it is larger than the sum of its proper divisors (7919151).
1220505542401 is an equidigital number, since it uses as much as digits as its factorization.
1220505542401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7919150.
The product of its (nonzero) digits is 16000, while the sum is 31.
The spelling of 1220505542401 in words is "one trillion, two hundred twenty billion, five hundred five million, five hundred forty-two thousand, four hundred one".
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