Base | Representation |
---|---|
bin | 10001110000101110101… |
… | …100011001000101111011 |
3 | 11022200110111212122001201 |
4 | 101300232230121011323 |
5 | 124444143322213430 |
6 | 2332414222155031 |
7 | 154116316452046 |
oct | 21605654310573 |
9 | 4280414778051 |
10 | 1220554101115 |
11 | 4306a7a74518 |
12 | 178675122a77 |
13 | 8b136a0a70b |
14 | 4310a249c5d |
15 | 21b394098ca |
hex | 11c2eb1917b |
1220554101115 has 16 divisors (see below), whose sum is σ = 1470057906240. Its totient is φ = 972848465280.
The previous prime is 1220554101083. The next prime is 1220554101157. The reversal of 1220554101115 is 5111014550221.
It is not a de Polignac number, because 1220554101115 - 25 = 1220554101083 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28771570 + ... + 28813960.
It is an arithmetic number, because the mean of its divisors is an integer number (91878619140).
Almost surely, 21220554101115 is an apocalyptic number.
1220554101115 is a deficient number, since it is larger than the sum of its proper divisors (249503805125).
1220554101115 is a wasteful number, since it uses less digits than its factorization.
1220554101115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63462.
The product of its (nonzero) digits is 2000, while the sum is 28.
Adding to 1220554101115 its reverse (5111014550221), we get a palindrome (6331568651336).
The spelling of 1220554101115 in words is "one trillion, two hundred twenty billion, five hundred fifty-four million, one hundred one thousand, one hundred fifteen".
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