1221034344531 has 4 divisors (see below), whose sum is σ = 1628045792712. Its totient is φ = 814022896352.

The previous prime is 1221034344511. The next prime is 1221034344599. The reversal of 1221034344531 is 1354434301221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1221034344531 - 2⁵ = 1221034344499 is a prime.

It is a super-2 number, since 2×1221034344531² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1221034344492 and 1221034344501.

It is not an unprimeable number, because it can be changed into a prime (1221034344511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 203505724086 + ... + 203505724091.

It is an arithmetic number, because the mean of its divisors is an integer number (407011448178).

Almost surely, 2^{1221034344531} is an apocalyptic number.

1221034344531 is a deficient number, since it is larger than the sum of its proper divisors (407011448181).

1221034344531 is an equidigital number, since it uses as much as digits as its factorization.

1221034344531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 407011448180.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 1221034344531 its reverse (1354434301221), we get a palindrome (2575468645752).

It can be divided in two parts, 1221034 and 344531, that added together give a triangular number (1565565 = T₁₇₆₉).

The spelling of 1221034344531 in words is "one trillion, two hundred twenty-one billion, thirty-four million, three hundred forty-four thousand, five hundred thirty-one".