1221122020433 has 16 divisors (see below), whose sum is σ = 1478903045760. Its totient is φ = 985935350400.

The previous prime is 1221122020379. The next prime is 1221122020499. The reversal of 1221122020433 is 3340202211221.

It is not a de Polignac number, because 1221122020433 - 2⁶ = 1221122020369 is a prime.

It is a super-4 number, since 4×1221122020433⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1221122020399 and 1221122020408.

It is not an unprimeable number, because it can be changed into a prime (1221122020033) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73349963 + ... + 73366608.

It is an arithmetic number, because the mean of its divisors is an integer number (92431440360).

Almost surely, 2^{1221122020433} is an apocalyptic number.

It is an amenable number.

1221122020433 is a deficient number, since it is larger than the sum of its proper divisors (257781025327).

1221122020433 is a wasteful number, since it uses less digits than its factorization.

1221122020433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 146716648.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1221122020433 its reverse (3340202211221), we get a palindrome (4561324231654).

The spelling of 1221122020433 in words is "one trillion, two hundred twenty-one billion, one hundred twenty-two million, twenty thousand, four hundred thirty-three".