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12211243403 = 22953324207
BaseRepresentation
bin10110101111101100…
…01100100110001011
31011112000121102211012
423113312030212023
5200002034242103
65335413154135
7611414566502
oct132766144613
934460542735
1012211243403
1151a6a239a7
12244962b94b
1311c7b57618
1483bac9839
154b709b2d8
hex2d7d8c98b

12211243403 has 4 divisors (see below), whose sum is σ = 12264567840. Its totient is φ = 12157918968.

The previous prime is 12211243391. The next prime is 12211243409. The reversal of 12211243403 is 30434211221.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30434211221 = 64783469787.

It is a cyclic number.

It is not a de Polignac number, because 12211243403 - 26 = 12211243339 is a prime.

It is a super-2 number, since 2×122112434032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12211243409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26661875 + ... + 26662332.

It is an arithmetic number, because the mean of its divisors is an integer number (3066141960).

Almost surely, 212211243403 is an apocalyptic number.

12211243403 is a deficient number, since it is larger than the sum of its proper divisors (53324437).

12211243403 is an equidigital number, since it uses as much as digits as its factorization.

12211243403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53324436.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12211243403 its reverse (30434211221), we get a palindrome (42645454624).

The spelling of 12211243403 in words is "twelve billion, two hundred eleven million, two hundred forty-three thousand, four hundred three".

Divisors: 1 229 53324207 12211243403