122113122001113 has 4 divisors (see below), whose sum is σ = 162817496001488. Its totient is φ = 81408748000740.

The previous prime is 122113122001111. The next prime is 122113122001121. The reversal of 122113122001113 is 311100221311221.

122113122001113 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 122113122001113 - 2¹ = 122113122001111 is a prime.

It is a super-2 number, since 2×122113122001113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 122113122001113.

It is not an unprimeable number, because it can be changed into a prime (122113122001111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20352187000183 + ... + 20352187000188.

It is an arithmetic number, because the mean of its divisors is an integer number (40704374000372).

Almost surely, 2^{122113122001113} is an apocalyptic number.

It is an amenable number.

122113122001113 is a deficient number, since it is larger than the sum of its proper divisors (40704374000375).

122113122001113 is an equidigital number, since it uses as much as digits as its factorization.

122113122001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40704374000374.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 122113122001113 its reverse (311100221311221), we get a palindrome (433213343312334).

The spelling of 122113122001113 in words is "one hundred twenty-two trillion, one hundred thirteen billion, one hundred twenty-two million, one thousand, one hundred thirteen".