Base | Representation |
---|---|
bin | 10001110001010001101… |
… | …100111110000010100011 |
3 | 11022201222110002022010201 |
4 | 101301101230332002203 |
5 | 130001344203030021 |
6 | 2332552403210031 |
7 | 154140011051062 |
oct | 21612154760243 |
9 | 4281873068121 |
10 | 1221141455011 |
11 | 430979575165 |
12 | 1787b9976917 |
13 | 8b1cb5c91ba |
14 | 431642601d9 |
15 | 21b70c7a591 |
hex | 11c51b3e0a3 |
1221141455011 has 4 divisors (see below), whose sum is σ = 1222430940072. Its totient is φ = 1219851969952.
The previous prime is 1221141454987. The next prime is 1221141455057. The reversal of 1221141455011 is 1105541411221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1221141455011 - 217 = 1221141323939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1221141455111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 644741110 + ... + 644743003.
It is an arithmetic number, because the mean of its divisors is an integer number (305607735018).
Almost surely, 21221141455011 is an apocalyptic number.
1221141455011 is a deficient number, since it is larger than the sum of its proper divisors (1289485061).
1221141455011 is an equidigital number, since it uses as much as digits as its factorization.
1221141455011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1289485060.
The product of its (nonzero) digits is 1600, while the sum is 28.
Adding to 1221141455011 its reverse (1105541411221), we get a palindrome (2326682866232).
The spelling of 1221141455011 in words is "one trillion, two hundred twenty-one billion, one hundred forty-one million, four hundred fifty-five thousand, eleven".
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