12211620144881 has 4 divisors (see below), whose sum is σ = 12211627141092. Its totient is φ = 12211613148672.

The previous prime is 12211620144859. The next prime is 12211620144887. The reversal of 12211620144881 is 18844102611221.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 7668579408400 + 4543040736481 = 2769220^2 + 2131441^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12211620144881 is a prime.

It is a super-3 number, since 3×12211620144881³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12211620144887) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1511321 + ... + 5167913.

It is an arithmetic number, because the mean of its divisors is an integer number (3052906785273).

Almost surely, 2^{12211620144881} is an apocalyptic number.

It is an amenable number.

12211620144881 is a deficient number, since it is larger than the sum of its proper divisors (6996211).

12211620144881 is an equidigital number, since it uses as much as digits as its factorization.

12211620144881 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6996210.

The product of its (nonzero) digits is 49152, while the sum is 41.

The spelling of 12211620144881 in words is "twelve trillion, two hundred eleven billion, six hundred twenty million, one hundred forty-four thousand, eight hundred eighty-one".