Search a number
-
+
122120210011 = 199909610879
BaseRepresentation
bin111000110111011101…
…1101000011001011011
3102200012202201102212011
41301232323220121123
54000100233210021
6132033511530351
711552152441462
oct1615673503133
9380182642764
10122120210011
11478777472a8
121b8019899b7
13b6925300c7
145ca6b739d9
15329b1b0de1
hex1c6eee865b

122120210011 has 4 divisors (see below), whose sum is σ = 122121020800. Its totient is φ = 122119399224.

The previous prime is 122120209963. The next prime is 122120210053. The reversal of 122120210011 is 110012021221.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 122120210011 - 215 = 122120177243 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 122120209973 and 122120210000.

It is not an unprimeable number, because it can be changed into a prime (122120210911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105531 + ... + 505348.

It is an arithmetic number, because the mean of its divisors is an integer number (30530255200).

Almost surely, 2122120210011 is an apocalyptic number.

122120210011 is a deficient number, since it is larger than the sum of its proper divisors (810789).

122120210011 is an equidigital number, since it uses as much as digits as its factorization.

122120210011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 810788.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 122120210011 its reverse (110012021221), we get a palindrome (232132231232).

The spelling of 122120210011 in words is "one hundred twenty-two billion, one hundred twenty million, two hundred ten thousand, eleven".

Divisors: 1 199909 610879 122120210011