Base | Representation |
---|---|
bin | 10001110001010101011… |
… | …101000110011100100011 |
3 | 11022202010211112102220212 |
4 | 101301111131012130203 |
5 | 130002011311412003 |
6 | 2333002532324335 |
7 | 154141404106613 |
oct | 21612535063443 |
9 | 4282124472825 |
10 | 1221204404003 |
11 | 430a0105a721 |
12 | 178816a736ab |
13 | 8b20b66951c |
14 | 4316c768a43 |
15 | 21b76561dd8 |
hex | 11c55746723 |
1221204404003 has 4 divisors (see below), whose sum is σ = 1224723725400. Its totient is φ = 1217685082608.
The previous prime is 1221204403999. The next prime is 1221204404027. The reversal of 1221204404003 is 3004044021221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1221204404003 - 22 = 1221204403999 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1221204404003.
It is not an unprimeable number, because it can be changed into a prime (1221204404083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1759660178 + ... + 1759660871.
It is an arithmetic number, because the mean of its divisors is an integer number (306180931350).
Almost surely, 21221204404003 is an apocalyptic number.
1221204404003 is a deficient number, since it is larger than the sum of its proper divisors (3519321397).
1221204404003 is an equidigital number, since it uses as much as digits as its factorization.
1221204404003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3519321396.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 1221204404003 its reverse (3004044021221), we get a palindrome (4225248425224).
The spelling of 1221204404003 in words is "one trillion, two hundred twenty-one billion, two hundred four million, four hundred four thousand, three".
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