Search a number
-
+
12212434433 = 191135688139
BaseRepresentation
bin10110101111110101…
…01111011000000001
31011112002211221121102
423113322233120001
5200002340400213
65335454504145
7611430660053
oct132772573001
934462757542
1012212434433
1151a7667821
122449b05055
1311c8183784
1483bd198d3
154b7234158
hex2d7eaf601

12212434433 has 8 divisors (see below), whose sum is σ = 12968959200. Its totient is φ = 11467286208.

The previous prime is 12212434387. The next prime is 12212434463. The reversal of 12212434433 is 33443421221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12212434433 - 228 = 11943998977 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12212434396 and 12212434405.

It is not an unprimeable number, because it can be changed into a prime (12212434463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2841923 + ... + 2846216.

It is an arithmetic number, because the mean of its divisors is an integer number (1621119900).

Almost surely, 212212434433 is an apocalyptic number.

It is an amenable number.

12212434433 is a deficient number, since it is larger than the sum of its proper divisors (756524767).

12212434433 is a wasteful number, since it uses less digits than its factorization.

12212434433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5688271.

The product of its digits is 13824, while the sum is 29.

Adding to 12212434433 its reverse (33443421221), we get a palindrome (45655855654).

The spelling of 12212434433 in words is "twelve billion, two hundred twelve million, four hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 19 113 2147 5688139 108074641 642759707 12212434433