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122132441003 = 749916286497
BaseRepresentation
bin111000110111110101…
…0010010011110101011
3102200020121201211121212
41301233222102132223
54000111401103003
6132035030023335
711552361422366
oct1615752223653
9380217654555
10122132441003
1147883640661
121b805aa7b4b
13b694c23291
145ca86390dd
15329c2c9dd8
hex1c6fa927ab

122132441003 has 4 divisors (see below), whose sum is σ = 122148735000. Its totient is φ = 122116147008.

The previous prime is 122132440999. The next prime is 122132441017. The reversal of 122132441003 is 300144231221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 122132441003 - 22 = 122132440999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 122132441003.

It is not an unprimeable number, because it can be changed into a prime (122132441033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8135750 + ... + 8150747.

It is an arithmetic number, because the mean of its divisors is an integer number (30537183750).

Almost surely, 2122132441003 is an apocalyptic number.

122132441003 is a deficient number, since it is larger than the sum of its proper divisors (16293997).

122132441003 is an equidigital number, since it uses as much as digits as its factorization.

122132441003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16293996.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 122132441003 its reverse (300144231221), we get a palindrome (422276672224).

The spelling of 122132441003 in words is "one hundred twenty-two billion, one hundred thirty-two million, four hundred forty-one thousand, three".

Divisors: 1 7499 16286497 122132441003