12214113 has 4 divisors (see below), whose sum is σ = 16285488. Its totient is φ = 8142740.

The previous prime is 12214099. The next prime is 12214159. The reversal of 12214113 is 31141221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31141221 = 3 ⋅10380407.

It is a cyclic number.

It is not a de Polignac number, because 12214113 - 2⁸ = 12213857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12214092 and 12214101.

It is not an unprimeable number, because it can be changed into a prime (12214183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2035683 + ... + 2035688.

It is an arithmetic number, because the mean of its divisors is an integer number (4071372).

Almost surely, 2^12214113 is an apocalyptic number.

It is an amenable number.

12214113 is a deficient number, since it is larger than the sum of its proper divisors (4071375).

12214113 is an equidigital number, since it uses as much as digits as its factorization.

12214113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4071374.

The product of its digits is 48, while the sum is 15.

The square root of 12214113 is about 3494.8695254616. The cubic root of 12214113 is about 230.2964859498.

Adding to 12214113 its reverse (31141221), we get a palindrome (43355334).

The spelling of 12214113 in words is "twelve million, two hundred fourteen thousand, one hundred thirteen".