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12214144433 = 19642849707
BaseRepresentation
bin10110110000000010…
…10000110110110001
31011112020001211021202
423120001100312301
5200003310110213
65335555300545
7611451341351
oct133001206661
934466054252
1012214144433
1151a8625547
12244a5aa755
1311c8631bca
1483c242b61
154b7470b58
hex2d8050db1

12214144433 has 4 divisors (see below), whose sum is σ = 12856994160. Its totient is φ = 11571294708.

The previous prime is 12214144379. The next prime is 12214144447. The reversal of 12214144433 is 33444141221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12214144433 - 28 = 12214144177 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12214144396 and 12214144405.

It is not an unprimeable number, because it can be changed into a prime (12214149433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321424835 + ... + 321424872.

It is an arithmetic number, because the mean of its divisors is an integer number (3214248540).

Almost surely, 212214144433 is an apocalyptic number.

It is an amenable number.

12214144433 is a deficient number, since it is larger than the sum of its proper divisors (642849727).

12214144433 is an equidigital number, since it uses as much as digits as its factorization.

12214144433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 642849726.

The product of its digits is 9216, while the sum is 29.

Adding to 12214144433 its reverse (33444141221), we get a palindrome (45658285654).

The spelling of 12214144433 in words is "twelve billion, two hundred fourteen million, one hundred forty-four thousand, four hundred thirty-three".

Divisors: 1 19 642849707 12214144433