Base | Representation |
---|---|
bin | 10110110000000011… |
… | …00011111001000001 |
3 | 1011112020012210020110 |
4 | 23120001203321001 |
5 | 200003320104101 |
6 | 5340001101533 |
7 | 611452114563 |
oct | 133001437101 |
9 | 34466183213 |
10 | 12214222401 |
11 | 51a8679087 |
12 | 244a6278a9 |
13 | 11c865b544 |
14 | 83c263333 |
15 | 4b7488cd6 |
hex | 2d8063e41 |
12214222401 has 4 divisors (see below), whose sum is σ = 16285629872. Its totient is φ = 8142814932.
The previous prime is 12214222379. The next prime is 12214222457. The reversal of 12214222401 is 10422241221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 12214222401 - 211 = 12214220353 is a prime.
It is a super-2 number, since 2×122142224012 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12214222201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2035703731 + ... + 2035703736.
It is an arithmetic number, because the mean of its divisors is an integer number (4071407468).
Almost surely, 212214222401 is an apocalyptic number.
It is an amenable number.
12214222401 is a deficient number, since it is larger than the sum of its proper divisors (4071407471).
12214222401 is an equidigital number, since it uses as much as digits as its factorization.
12214222401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4071407470.
The product of its (nonzero) digits is 512, while the sum is 21.
Adding to 12214222401 its reverse (10422241221), we get a palindrome (22636463622).
The spelling of 12214222401 in words is "twelve billion, two hundred fourteen million, two hundred twenty-two thousand, four hundred one".
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