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1222102113 = 3795156549
BaseRepresentation
bin100100011010111…
…1100110001100001
310011011121012221020
41020311330301201
510000324231423
6321133520053
742166460631
oct11065746141
93134535836
101222102113
11577932451
122a1343029
1316626265b
14b84446c1
15724544e3
hex48d7cc61

1222102113 has 8 divisors (see below), whose sum is σ = 1650096000. Its totient is φ = 804421488.

The previous prime is 1222102111. The next prime is 1222102139. The reversal of 1222102113 is 3112012221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1222102113 - 21 = 1222102111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1222102092 and 1222102101.

It is not an unprimeable number, because it can be changed into a prime (1222102111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2578038 + ... + 2578511.

It is an arithmetic number, because the mean of its divisors is an integer number (206262000).

Almost surely, 21222102113 is an apocalyptic number.

It is an amenable number.

1222102113 is a deficient number, since it is larger than the sum of its proper divisors (427993887).

1222102113 is an equidigital number, since it uses as much as digits as its factorization.

1222102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5156631.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1222102113 is about 34958.5771020504. The cubic root of 1222102113 is about 1069.1430857191.

Adding to 1222102113 its reverse (3112012221), we get a palindrome (4334114334).

The spelling of 1222102113 in words is "one billion, two hundred twenty-two million, one hundred two thousand, one hundred thirteen".

Divisors: 1 3 79 237 5156549 15469647 407367371 1222102113