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12221210113 = 71745887159
BaseRepresentation
bin10110110000111000…
…01101111000000001
31011112201100210120121
423120130031320001
5200012112210423
65340410540241
7611565400120
oct133034157001
934481323517
1012221210113
115201611052
122450a37681
1311c9c36c98
1483d161ab7
154b7db945d
hex2d870de01

12221210113 has 4 divisors (see below), whose sum is σ = 13967097280. Its totient is φ = 10475322948.

The previous prime is 12221210059. The next prime is 12221210137. The reversal of 12221210113 is 31101212221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31101212221 = 76940443709.

It is a cyclic number.

It is not a de Polignac number, because 12221210113 - 213 = 12221201921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12221210173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 872943573 + ... + 872943586.

It is an arithmetic number, because the mean of its divisors is an integer number (3491774320).

Almost surely, 212221210113 is an apocalyptic number.

It is an amenable number.

12221210113 is a deficient number, since it is larger than the sum of its proper divisors (1745887167).

12221210113 is an equidigital number, since it uses as much as digits as its factorization.

12221210113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1745887166.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12221210113 its reverse (31101212221), we get a palindrome (43322422334).

The spelling of 12221210113 in words is "twelve billion, two hundred twenty-one million, two hundred ten thousand, one hundred thirteen".

Divisors: 1 7 1745887159 12221210113