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12222450643 = 13940188511
BaseRepresentation
bin10110110001000001…
…11100101111010011
31011112210200211021011
423120200330233103
5200012421410033
65340453311351
7611612054614
oct133040745723
934483624234
1012222450643
115202289087
122451335557
1311ca27c820
1483d3a5c0b
154b8061ccd
hex2d883cbd3

12222450643 has 4 divisors (see below), whose sum is σ = 13162639168. Its totient is φ = 11282262120.

The previous prime is 12222450637. The next prime is 12222450659. The reversal of 12222450643 is 34605422221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12222450643 - 225 = 12188896211 is a prime.

It is a super-2 number, since 2×122224506432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12222450043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 470094243 + ... + 470094268.

It is an arithmetic number, because the mean of its divisors is an integer number (3290659792).

Almost surely, 212222450643 is an apocalyptic number.

12222450643 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

12222450643 is a deficient number, since it is larger than the sum of its proper divisors (940188525).

12222450643 is an equidigital number, since it uses as much as digits as its factorization.

12222450643 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 940188524.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 12222450643 its reverse (34605422221), we get a palindrome (46827872864).

The spelling of 12222450643 in words is "twelve billion, two hundred twenty-two million, four hundred fifty thousand, six hundred forty-three".

Divisors: 1 13 940188511 12222450643