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12223042113 = 34074347371
BaseRepresentation
bin10110110001000110…
…01101001001000001
31011112211210212121110
423120203031021001
5200013044321423
65340514113533
7611620100202
oct133043151101
934484725543
1012223042113
1152026524a7
12245157b8a9
1311ca428ac9
1483d4bb5a9
154b812c193
hex2d88cd241

12223042113 has 4 divisors (see below), whose sum is σ = 16297389488. Its totient is φ = 8148694740.

The previous prime is 12223042087. The next prime is 12223042127. The reversal of 12223042113 is 31124032221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12223042113 - 25 = 12223042081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12223042113.

It is not an unprimeable number, because it can be changed into a prime (12223042193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2037173683 + ... + 2037173688.

It is an arithmetic number, because the mean of its divisors is an integer number (4074347372).

Almost surely, 212223042113 is an apocalyptic number.

It is an amenable number.

12223042113 is a deficient number, since it is larger than the sum of its proper divisors (4074347375).

12223042113 is an equidigital number, since it uses as much as digits as its factorization.

12223042113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4074347374.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 12223042113 its reverse (31124032221), we get a palindrome (43347074334).

The spelling of 12223042113 in words is "twelve billion, two hundred twenty-three million, forty-two thousand, one hundred thirteen".

Divisors: 1 3 4074347371 12223042113