Base | Representation |
---|---|
bin | 10110110001001001… |
… | …01110010011111001 |
3 | 1011112212120002120111 |
4 | 23120210232103321 |
5 | 200013200040441 |
6 | 5340530424321 |
7 | 611623345444 |
oct | 133044562371 |
9 | 34485502514 |
10 | 12223440121 |
11 | 52028a4532 |
12 | 24517320a1 |
13 | 11ca538009 |
14 | 83d58265b |
15 | 4b81aa081 |
hex | 2d892e4f9 |
12223440121 has 4 divisors (see below), whose sum is σ = 12224740752. Its totient is φ = 12222139492.
The previous prime is 12223440101. The next prime is 12223440127. The reversal of 12223440121 is 12104432221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12223440121 - 233 = 3633505529 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12223440092 and 12223440101.
It is not an unprimeable number, because it can be changed into a prime (12223440127) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 636115 + ... + 655048.
It is an arithmetic number, because the mean of its divisors is an integer number (3056185188).
Almost surely, 212223440121 is an apocalyptic number.
It is an amenable number.
12223440121 is a deficient number, since it is larger than the sum of its proper divisors (1300631).
12223440121 is an equidigital number, since it uses as much as digits as its factorization.
12223440121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1300630.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 12223440121 its reverse (12104432221), we get a palindrome (24327872342).
The spelling of 12223440121 in words is "twelve billion, two hundred twenty-three million, four hundred forty thousand, one hundred twenty-one".
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