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12224304433 = 111111300403
BaseRepresentation
bin10110110001010000…
…00001010100110001
31011112221012000012001
423120220001110301
5200013410220213
65341001134001
7611633605345
oct133050012461
934487160161
1012224304433
115203334940
122451a8a301
1311ca77b543
1483d729625
154b82cb1dd
hex2d8a01531

12224304433 has 4 divisors (see below), whose sum is σ = 13335604848. Its totient is φ = 11113004020.

The previous prime is 12224304419. The next prime is 12224304439. The reversal of 12224304433 is 33440342221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12224304433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12224304439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 555650191 + ... + 555650212.

It is an arithmetic number, because the mean of its divisors is an integer number (3333901212).

Almost surely, 212224304433 is an apocalyptic number.

It is an amenable number.

12224304433 is a deficient number, since it is larger than the sum of its proper divisors (1111300415).

12224304433 is a wasteful number, since it uses less digits than its factorization.

12224304433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1111300414.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 12224304433 its reverse (33440342221), we get a palindrome (45664646654).

The spelling of 12224304433 in words is "twelve billion, two hundred twenty-four million, three hundred four thousand, four hundred thirty-three".

Divisors: 1 11 1111300403 12224304433