122311145341041 has 4 divisors (see below), whose sum is σ = 163081527121392. Its totient is φ = 81540763560692.

The previous prime is 122311145341037. The next prime is 122311145341057. The reversal of 122311145341041 is 140143541113221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 122311145341041 - 2² = 122311145341037 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 122311145340993 and 122311145341011.

It is not an unprimeable number, because it can be changed into a prime (122311145341741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20385190890171 + ... + 20385190890176.

It is an arithmetic number, because the mean of its divisors is an integer number (40770381780348).

Almost surely, 2^{122311145341041} is an apocalyptic number.

It is an amenable number.

122311145341041 is a deficient number, since it is larger than the sum of its proper divisors (40770381780351).

122311145341041 is an equidigital number, since it uses as much as digits as its factorization.

122311145341041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40770381780350.

The product of its (nonzero) digits is 11520, while the sum is 33.

Adding to 122311145341041 its reverse (140143541113221), we get a palindrome (262454686454262).

The spelling of 122311145341041 in words is "one hundred twenty-two trillion, three hundred eleven billion, one hundred forty-five million, three hundred forty-one thousand, forty-one".