Base | Representation |
---|---|
bin | 11011110100001001101111… |
… | …000010110010001010011001 |
3 | 121001010202000012012012122120 |
4 | 123310021233002302022121 |
5 | 112013233114102303101 |
6 | 1112102050313211453 |
7 | 34524063142211025 |
oct | 3364115702621231 |
9 | 531122005165576 |
10 | 122331121525401 |
11 | 35a84378a31a18 |
12 | 11878711100b89 |
13 | 5334a10331219 |
14 | 222cc0200d385 |
15 | e221a7104b36 |
hex | 6f426f0b2299 |
122331121525401 has 16 divisors (see below), whose sum is σ = 164033997492480. Its totient is φ = 81092177349120.
The previous prime is 122331121525399. The next prime is 122331121525421. The reversal of 122331121525401 is 104525121133221.
It is not a de Polignac number, because 122331121525401 - 21 = 122331121525399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (122331121525421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 126274690 + ... + 127239771.
It is an arithmetic number, because the mean of its divisors is an integer number (10252124843280).
Almost surely, 2122331121525401 is an apocalyptic number.
It is an amenable number.
122331121525401 is a deficient number, since it is larger than the sum of its proper divisors (41702875967079).
122331121525401 is a wasteful number, since it uses less digits than its factorization.
122331121525401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 253515376.
The product of its (nonzero) digits is 14400, while the sum is 33.
Adding to 122331121525401 its reverse (104525121133221), we get a palindrome (226856242658622).
The spelling of 122331121525401 in words is "one hundred twenty-two trillion, three hundred thirty-one billion, one hundred twenty-one million, five hundred twenty-five thousand, four hundred one".
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