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122334143113 = 71312591067777
BaseRepresentation
bin111000111101110101…
…1101110001010001001
3102200202200021100220101
41301323223232022021
54001020020034423
6132111033125401
711560361026240
oct1617353561211
9380680240811
10122334143113
1147977486416
121b861559861
13b6c7955240
145cc7341957
1532aed6d7ad
hex1c7baee289

122334143113 has 16 divisors (see below), whose sum is σ = 150684831360. Its totient is φ = 96714878976.

The previous prime is 122334143077. The next prime is 122334143221. The reversal of 122334143113 is 311341433221.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122334143113 is a prime.

It is a super-3 number, since 3×1223341431133 (a number of 34 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (122334141113) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 419320 + ... + 648457.

It is an arithmetic number, because the mean of its divisors is an integer number (9417801960).

Almost surely, 2122334143113 is an apocalyptic number.

122334143113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

122334143113 is a deficient number, since it is larger than the sum of its proper divisors (28350688247).

122334143113 is a wasteful number, since it uses less digits than its factorization.

122334143113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1069056.

The product of its digits is 5184, while the sum is 28.

Adding to 122334143113 its reverse (311341433221), we get a palindrome (433675576334).

The spelling of 122334143113 in words is "one hundred twenty-two billion, three hundred thirty-four million, one hundred forty-three thousand, one hundred thirteen".

Divisors: 1 7 13 91 1259 8813 16367 114569 1067777 7474439 13881101 97167707 1344331243 9410318701 17476306159 122334143113