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1223450011153 = 5967933052619
BaseRepresentation
bin10001110011011011010…
…011011010011000010001
311022221221100001002211001
4101303123103122120101
5130021111200324103
62334013431422001
7154251142336336
oct21633323323021
94287840032731
101223450011153
114319536aa5a7
12179142b24901
138b4a8978956
1443302ab898d
1521c5878c01d
hex11cdb4da611

1223450011153 has 8 divisors (see below), whose sum is σ = 1244370016800. Its totient is φ = 1202536124448.

The previous prime is 1223450011141. The next prime is 1223450011211. The reversal of 1223450011153 is 3511100543221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1223450011153 - 29 = 1223450010641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1223450011123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1125523 + ... + 1927096.

It is an arithmetic number, because the mean of its divisors is an integer number (155546252100).

Almost surely, 21223450011153 is an apocalyptic number.

It is an amenable number.

1223450011153 is a deficient number, since it is larger than the sum of its proper divisors (20920005647).

1223450011153 is an equidigital number, since it uses as much as digits as its factorization.

1223450011153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3059471.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 1223450011153 its reverse (3511100543221), we get a palindrome (4734550554374).

The spelling of 1223450011153 in words is "one trillion, two hundred twenty-three billion, four hundred fifty million, eleven thousand, one hundred fifty-three".

Divisors: 1 59 6793 400787 3052619 180104521 20736440867 1223450011153