Base | Representation |
---|---|
bin | 11011110100010110110010… |
… | …000001110011100011111001 |
3 | 121001012002011111001212100221 |
4 | 123310112302001303203321 |
5 | 112014000311320304340 |
6 | 1112112324340500041 |
7 | 34525100244312151 |
oct | 3364266201634371 |
9 | 531162144055327 |
10 | 122345130244345 |
11 | 35a8a307545898 |
12 | 1187b3806aa621 |
13 | 53361336a3828 |
14 | 222d770715761 |
15 | e22726dab44a |
hex | 6f45b20738f9 |
122345130244345 has 4 divisors (see below), whose sum is σ = 146814156293220. Its totient is φ = 97876104195472.
The previous prime is 122345130244327. The next prime is 122345130244391. The reversal of 122345130244345 is 543442031543221.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 29608692483769 + 92736437760576 = 5441387^2 + 9629976^2 .
It is a cyclic number.
It is not a de Polignac number, because 122345130244345 - 219 = 122345129720057 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12234513024430 + ... + 12234513024439.
It is an arithmetic number, because the mean of its divisors is an integer number (36703539073305).
Almost surely, 2122345130244345 is an apocalyptic number.
It is an amenable number.
122345130244345 is a deficient number, since it is larger than the sum of its proper divisors (24469026048875).
122345130244345 is an equidigital number, since it uses as much as digits as its factorization.
122345130244345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24469026048874.
The product of its (nonzero) digits is 1382400, while the sum is 43.
Adding to 122345130244345 its reverse (543442031543221), we get a palindrome (665787161787566).
The spelling of 122345130244345 in words is "one hundred twenty-two trillion, three hundred forty-five billion, one hundred thirty million, two hundred forty-four thousand, three hundred forty-five".
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