Base | Representation |
---|---|
bin | 11011110101001010011001… |
… | …011011110010111100100001 |
3 | 121001101101012221021000122220 |
4 | 123311022121123302330201 |
5 | 112020402312330431032 |
6 | 1112154012025421253 |
7 | 34532101534215525 |
oct | 3365123133627441 |
9 | 531341187230586 |
10 | 122400552202017 |
11 | 360008678189a1 |
12 | 1188a06933a829 |
13 | 533b426830c1b |
14 | 223230b185d85 |
15 | e23dbc75712c |
hex | 6f52996f2f21 |
122400552202017 has 4 divisors (see below), whose sum is σ = 163200736269360. Its totient is φ = 81600368134676.
The previous prime is 122400552202013. The next prime is 122400552202057. The reversal of 122400552202017 is 710202255004221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 122400552202017 - 22 = 122400552202013 is a prime.
It is not an unprimeable number, because it can be changed into a prime (122400552202013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20400092033667 + ... + 20400092033672.
It is an arithmetic number, because the mean of its divisors is an integer number (40800184067340).
Almost surely, 2122400552202017 is an apocalyptic number.
It is an amenable number.
122400552202017 is a deficient number, since it is larger than the sum of its proper divisors (40800184067343).
122400552202017 is an equidigital number, since it uses as much as digits as its factorization.
122400552202017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40800184067342.
The product of its (nonzero) digits is 22400, while the sum is 33.
The spelling of 122400552202017 in words is "one hundred twenty-two trillion, four hundred billion, five hundred fifty-two million, two hundred two thousand, seventeen".
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