1224340113 has 4 divisors (see below), whose sum is σ = 1632453488. Its totient is φ = 816226740.

The previous prime is 1224340097. The next prime is 1224340141. The reversal of 1224340113 is 3110434221.

1224340113 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3110434221 = 3 ⋅1036811407.

It is not a de Polignac number, because 1224340113 - 2⁴ = 1224340097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1224340113.

It is not an unprimeable number, because it can be changed into a prime (1224340213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204056683 + ... + 204056688.

It is an arithmetic number, because the mean of its divisors is an integer number (408113372).

Almost surely, 2^1224340113 is an apocalyptic number.

It is an amenable number.

1224340113 is a deficient number, since it is larger than the sum of its proper divisors (408113375).

1224340113 is an equidigital number, since it uses as much as digits as its factorization.

1224340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 408113374.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 1224340113 is about 34990.5717729791. The cubic root of 1224340113 is about 1069.7953179394.

Adding to 1224340113 its reverse (3110434221), we get a palindrome (4334774334).

The spelling of 1224340113 in words is "one billion, two hundred twenty-four million, three hundred forty thousand, one hundred thirteen".