Base | Representation |
---|---|
bin | 10110110011100001… |
… | …11011000001001001 |
3 | 1011121021010221010000 |
4 | 23121300323001021 |
5 | 200033303240423 |
6 | 5342522513213 |
7 | 612255211536 |
oct | 133160730111 |
9 | 34537127100 |
10 | 12243415113 |
11 | 52130a7a96 |
12 | 2458365809 |
13 | 120170cc37 |
14 | 8420a1d8d |
15 | 4b9d03843 |
hex | 2d9c3b049 |
12243415113 has 40 divisors (see below), whose sum is σ = 19654585632. Its totient is φ = 7567426944.
The previous prime is 12243415049. The next prime is 12243415153. The reversal of 12243415113 is 31151434221.
12243415113 is a `hidden beast` number, since 1 + 2 + 243 + 415 + 1 + 1 + 3 = 666.
It is not a de Polignac number, because 12243415113 - 26 = 12243415049 is a prime.
It is a super-3 number, since 3×122434151133 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (12243415153) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 25906 + ... + 158612.
Almost surely, 212243415113 is an apocalyptic number.
It is an amenable number.
12243415113 is a deficient number, since it is larger than the sum of its proper divisors (7411170519).
12243415113 is a wasteful number, since it uses less digits than its factorization.
12243415113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132803 (or 132794 counting only the distinct ones).
The product of its digits is 2880, while the sum is 27.
Adding to 12243415113 its reverse (31151434221), we get a palindrome (43394849334).
The spelling of 12243415113 in words is "twelve billion, two hundred forty-three million, four hundred fifteen thousand, one hundred thirteen".
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