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122530001441 = 2331716805651
BaseRepresentation
bin111001000011101011…
…0110111001000100001
3102201021022211000000112
41302013112313020201
54001420140021231
6132142311101105
711565256553621
oct1620726671041
9381238730015
10122530001441
1147a67a9a701
121b8b7071795
13b7293bc343
145d05366881
1532c215a92b
hex1c875b7221

122530001441 has 8 divisors (see below), whose sum is σ = 128260736064. Its totient is φ = 116832878800.

The previous prime is 122530001411. The next prime is 122530001459. The reversal of 122530001441 is 144100035221.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122530001441 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (122530001401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8395535 + ... + 8410116.

It is an arithmetic number, because the mean of its divisors is an integer number (16032592008).

Almost surely, 2122530001441 is an apocalyptic number.

It is an amenable number.

122530001441 is a deficient number, since it is larger than the sum of its proper divisors (5730734623).

122530001441 is a wasteful number, since it uses less digits than its factorization.

122530001441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16805991.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 122530001441 its reverse (144100035221), we get a palindrome (266630036662).

The spelling of 122530001441 in words is "one hundred twenty-two billion, five hundred thirty million, one thousand, four hundred forty-one".

Divisors: 1 23 317 7291 16805651 386529973 5327391367 122530001441