Base | Representation |
---|---|
bin | 1011001001001110000110… |
… | …1100101011000010110011 |
3 | 1121101101012221220012022201 |
4 | 2302103201230223002303 |
5 | 3101223203011444220 |
6 | 42020544340044031 |
7 | 2403152405460526 |
oct | 262234154530263 |
9 | 47341187805281 |
10 | 12253033312435 |
11 | 39a4533961633 |
12 | 145a878093617 |
13 | 6ab5c10278b6 |
14 | 30509b1c8bbd |
15 | 163ae21add0a |
hex | b24e1b2b0b3 |
12253033312435 has 8 divisors (see below), whose sum is σ = 15062265340416. Its totient is φ = 9563343072960.
The previous prime is 12253033312417. The next prime is 12253033312459. The reversal of 12253033312435 is 53421333035221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12253033312435 - 211 = 12253033310387 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12253033312394 and 12253033312403.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29885446899 + ... + 29885447308.
It is an arithmetic number, because the mean of its divisors is an integer number (1882783167552).
Almost surely, 212253033312435 is an apocalyptic number.
12253033312435 is a deficient number, since it is larger than the sum of its proper divisors (2809232027981).
12253033312435 is an equidigital number, since it uses as much as digits as its factorization.
12253033312435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59770894253.
The product of its (nonzero) digits is 194400, while the sum is 37.
Adding to 12253033312435 its reverse (53421333035221), we get a palindrome (65674366347656).
The spelling of 12253033312435 in words is "twelve trillion, two hundred fifty-three billion, thirty-three million, three hundred twelve thousand, four hundred thirty-five".
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